3(b-5)+6(2b-1)=7(2b+1)

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Solution for 3(b-5)+6(2b-1)=7(2b+1) equation:


Simplifying
3(b + -5) + 6(2b + -1) = 7(2b + 1)

Reorder the terms:
3(-5 + b) + 6(2b + -1) = 7(2b + 1)
(-5 * 3 + b * 3) + 6(2b + -1) = 7(2b + 1)
(-15 + 3b) + 6(2b + -1) = 7(2b + 1)

Reorder the terms:
-15 + 3b + 6(-1 + 2b) = 7(2b + 1)
-15 + 3b + (-1 * 6 + 2b * 6) = 7(2b + 1)
-15 + 3b + (-6 + 12b) = 7(2b + 1)

Reorder the terms:
-15 + -6 + 3b + 12b = 7(2b + 1)

Combine like terms: -15 + -6 = -21
-21 + 3b + 12b = 7(2b + 1)

Combine like terms: 3b + 12b = 15b
-21 + 15b = 7(2b + 1)

Reorder the terms:
-21 + 15b = 7(1 + 2b)
-21 + 15b = (1 * 7 + 2b * 7)
-21 + 15b = (7 + 14b)

Solving
-21 + 15b = 7 + 14b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-14b' to each side of the equation.
-21 + 15b + -14b = 7 + 14b + -14b

Combine like terms: 15b + -14b = 1b
-21 + 1b = 7 + 14b + -14b

Combine like terms: 14b + -14b = 0
-21 + 1b = 7 + 0
-21 + 1b = 7

Add '21' to each side of the equation.
-21 + 21 + 1b = 7 + 21

Combine like terms: -21 + 21 = 0
0 + 1b = 7 + 21
1b = 7 + 21

Combine like terms: 7 + 21 = 28
1b = 28

Divide each side by '1'.
b = 28

Simplifying
b = 28

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