3(b-4)=8(b+5)-12

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Solution for 3(b-4)=8(b+5)-12 equation:


Simplifying
3(b + -4) = 8(b + 5) + -12

Reorder the terms:
3(-4 + b) = 8(b + 5) + -12
(-4 * 3 + b * 3) = 8(b + 5) + -12
(-12 + 3b) = 8(b + 5) + -12

Reorder the terms:
-12 + 3b = 8(5 + b) + -12
-12 + 3b = (5 * 8 + b * 8) + -12
-12 + 3b = (40 + 8b) + -12

Reorder the terms:
-12 + 3b = 40 + -12 + 8b

Combine like terms: 40 + -12 = 28
-12 + 3b = 28 + 8b

Solving
-12 + 3b = 28 + 8b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-8b' to each side of the equation.
-12 + 3b + -8b = 28 + 8b + -8b

Combine like terms: 3b + -8b = -5b
-12 + -5b = 28 + 8b + -8b

Combine like terms: 8b + -8b = 0
-12 + -5b = 28 + 0
-12 + -5b = 28

Add '12' to each side of the equation.
-12 + 12 + -5b = 28 + 12

Combine like terms: -12 + 12 = 0
0 + -5b = 28 + 12
-5b = 28 + 12

Combine like terms: 28 + 12 = 40
-5b = 40

Divide each side by '-5'.
b = -8

Simplifying
b = -8

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