3(b-4)=6-2(b-6)

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Solution for 3(b-4)=6-2(b-6) equation: 



3(b-4)=6-2(b-6)

We move all terms to the left:

3(b-4)-(6-2(b-6))=0

We multiply parentheses

3b-(6-2(b-6))-12=0



We calculate terms in parentheses: -(6-2(b-6)), so:

6-2(b-6)

determiningTheFunctionDomain
-2(b-6)+6

We multiply parentheses

-2b+12+6

We add all the numbers together, and all the variables

-2b+18

Back to the equation:

-(-2b+18)



We get rid of parentheses

3b+2b-18-12=0

We add all the numbers together, and all the variables

5b-30=0

We move all terms containing b to the left, all other terms to the right

5b=30

b=30/5

b=6

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