3(b-4)=5b2

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Solution for 3(b-4)=5b2 equation: 



3(b-4)=5b^2

We move all terms to the left:

3(b-4)-(5b^2)=0

determiningTheFunctionDomain
-5b^2+3(b-4)=0

We multiply parentheses

-5b^2+3b-12=0

a = -5; b = 3; c = -12;
Δ = b2-4ac
Δ = 32-4·(-5)·(-12)
Δ = -231
Delta is less than zero, so there is no solution for the equation

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