3(b-4)=5-2(b+8)

Solution for 3(b-4)=5-2(b+8) equation:

3(b-4)=5-2(b+8)

We move all terms to the left:

3(b-4)-(5-2(b+8))=0

We multiply parentheses

3b-(5-2(b+8))-12=0


We calculate terms in parentheses: -(5-2(b+8)), so:

5-2(b+8)

determiningTheFunctionDomain
-2(b+8)+5

We multiply parentheses

-2b-16+5

We add all the numbers together, and all the variables

-2b-11

Back to the equation:

-(-2b-11)


We get rid of parentheses

3b+2b+11-12=0

We add all the numbers together, and all the variables

5b-1=0

We move all terms containing b to the left, all other terms to the right

5b=1

b=1/5

b=1/5