3(b-3)=b+1

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Solution for 3(b-3)=b+1 equation: 



3(b-3)=b+1

We move all terms to the left:

3(b-3)-(b+1)=0

We multiply parentheses

3b-(b+1)-9=0

We get rid of parentheses

3b-b-1-9=0

We add all the numbers together, and all the variables

2b-10=0

We move all terms containing b to the left, all other terms to the right

2b=10

b=10/2

b=5

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