3(b-3)=2(5b+10)

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Solution for 3(b-3)=2(5b+10) equation: 



3(b-3)=2(5b+10)

We move all terms to the left:

3(b-3)-(2(5b+10))=0

We multiply parentheses

3b-(2(5b+10))-9=0



We calculate terms in parentheses: -(2(5b+10)), so:

2(5b+10)

We multiply parentheses

10b+20

Back to the equation:

-(10b+20)



We get rid of parentheses

3b-10b-20-9=0

We add all the numbers together, and all the variables

-7b-29=0

We move all terms containing b to the left, all other terms to the right

-7b=29

b=29/-7

b=-4+1/7

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