3(b-20)+2b=140

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Solution for 3(b-20)+2b=140 equation: 



3(b-20)+2b=140

We move all terms to the left:

3(b-20)+2b-(140)=0

We add all the numbers together, and all the variables

2b+3(b-20)-140=0

We multiply parentheses

2b+3b-60-140=0

We add all the numbers together, and all the variables

5b-200=0

We move all terms containing b to the left, all other terms to the right

5b=200

b=200/5

b=40

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