3(b-2)=6-b

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Solution for 3(b-2)=6-b equation: 



3(b-2)=6-b

We move all terms to the left:

3(b-2)-(6-b)=0

We add all the numbers together, and all the variables

3(b-2)-(-1b+6)=0

We multiply parentheses

3b-(-1b+6)-6=0

We get rid of parentheses

3b+1b-6-6=0

We add all the numbers together, and all the variables

4b-12=0

We move all terms containing b to the left, all other terms to the right

4b=12

b=12/4

b=3

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