3(b-2)/7=2(b+3)/8

Solution for 3(b-2)/7=2(b+3)/8 equation:

3(b-2)/7=2(b+3)/8

We move all terms to the left:

3(b-2)/7-(2(b+3)/8)=0

We calculate fractions


3b/()+(-(2(b+3)*7)/()=0


We calculate terms in parentheses: +(-(2(b+3)*7)/(), so:

-(2(b+3)*7)/(

We multiply all the terms by the denominator


-(2(b+3)*7)


We calculate terms in parentheses: -(2(b+3)*7), so:

2(b+3)*7

We multiply parentheses

14b+42

Back to the equation:

-(14b+42)


We get rid of parentheses

-14b-42

Back to the equation:

+(-14b-42)


We get rid of parentheses

3b/()-14b-42=0

We multiply all the terms by the denominator


3b-14b*()-42*()=0

We add all the numbers together, and all the variables

3b-14b*()=0