3(b-2)-2(b-4)=5(b+1)

Solution for 3(b-2)-2(b-4)=5(b+1) equation:

Simplifying
3(b + -2) + -2(b + -4) = 5(b + 1)

Reorder the terms:
3(-2 + b) + -2(b + -4) = 5(b + 1)
(-2 * 3 + b * 3) + -2(b + -4) = 5(b + 1)
(-6 + 3b) + -2(b + -4) = 5(b + 1)

Reorder the terms:
-6 + 3b + -2(-4 + b) = 5(b + 1)
-6 + 3b + (-4 * -2 + b * -2) = 5(b + 1)
-6 + 3b + (8 + -2b) = 5(b + 1)

Reorder the terms:
-6 + 8 + 3b + -2b = 5(b + 1)

Combine like terms: -6 + 8 = 2
2 + 3b + -2b = 5(b + 1)

Combine like terms: 3b + -2b = 1b
2 + 1b = 5(b + 1)

Reorder the terms:
2 + 1b = 5(1 + b)
2 + 1b = (1 * 5 + b * 5)
2 + 1b = (5 + 5b)

Solving
2 + 1b = 5 + 5b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5b' to each side of the equation.
2 + 1b + -5b = 5 + 5b + -5b

Combine like terms: 1b + -5b = -4b
2 + -4b = 5 + 5b + -5b

Combine like terms: 5b + -5b = 0
2 + -4b = 5 + 0
2 + -4b = 5

Add '-2' to each side of the equation.
2 + -2 + -4b = 5 + -2

Combine like terms: 2 + -2 = 0
0 + -4b = 5 + -2
-4b = 5 + -2

Combine like terms: 5 + -2 = 3
-4b = 3

Divide each side by '-4'.
b = -0.75

Simplifying
b = -0.75