3(b-2)+5=7+3(2-5)-38

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Solution for 3(b-2)+5=7+3(2-5)-38 equation: 



3(b-2)+5=7+3(2-5)-38

We move all terms to the left:

3(b-2)+5-(7+3(2-5)-38)=0

We add all the numbers together, and all the variables

3(b-2)+5-(7+3(-3)-38)=0

We add all the numbers together, and all the variables

3(b-2)+45=0

We multiply parentheses

3b-6+45=0

We add all the numbers together, and all the variables

3b+39=0

We move all terms containing b to the left, all other terms to the right

3b=-39

b=-39/3

b=-13

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