3(b-12)=3b(7)

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Solution for 3(b-12)=3b(7) equation: 



3(b-12)=3b(7)

We move all terms to the left:

3(b-12)-(3b(7))=0

determiningTheFunctionDomain
3(b-12)-3b7=0

We add all the numbers together, and all the variables

-3b^7+3(b-12)=0

We multiply parentheses

-3b^7+3b-36=0

We do not support ebpression: b^7

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