3(b-12)-6=18

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Solution for 3(b-12)-6=18 equation: 



3(b-12)-6=18

We move all terms to the left:

3(b-12)-6-(18)=0

We add all the numbers together, and all the variables

3(b-12)-24=0

We multiply parentheses

3b-36-24=0

We add all the numbers together, and all the variables

3b-60=0

We move all terms containing b to the left, all other terms to the right

3b=60

b=60/3

b=20

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