3(b-12)+b=1/2(12-8b)

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Solution for 3(b-12)+b=1/2(12-8b) equation: 



3(b-12)+b=1/2(12-8b)

We move all terms to the left:

3(b-12)+b-(1/2(12-8b))=0



Domain of the equation: 2(12-8b))!=0

b∈R



We add all the numbers together, and all the variables

3(b-12)+b-(1/2(-8b+12))=0

We add all the numbers together, and all the variables

b+3(b-12)-(1/2(-8b+12))=0

We multiply parentheses

b+3b-(1/2(-8b+12))-36=0

We multiply all the terms by the denominator


b*2(-8b+12))+3b*2(-8b-8b+12))-(1-36*2(+12))=0

We add all the numbers together, and all the variables

b*2(-8b+12))+3b*2(-16b+12))-(1-36*212)=0

We add all the numbers together, and all the variables

-16b+b*2(-8b+12))+3b*2(=0

Wy multiply elements

4b^3(--16b=0

We do not support ebpression: b^3(

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