3(b+6)+5(b+2)=68

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Solution for 3(b+6)+5(b+2)=68 equation:


Simplifying
3(b + 6) + 5(b + 2) = 68

Reorder the terms:
3(6 + b) + 5(b + 2) = 68
(6 * 3 + b * 3) + 5(b + 2) = 68
(18 + 3b) + 5(b + 2) = 68

Reorder the terms:
18 + 3b + 5(2 + b) = 68
18 + 3b + (2 * 5 + b * 5) = 68
18 + 3b + (10 + 5b) = 68

Reorder the terms:
18 + 10 + 3b + 5b = 68

Combine like terms: 18 + 10 = 28
28 + 3b + 5b = 68

Combine like terms: 3b + 5b = 8b
28 + 8b = 68

Solving
28 + 8b = 68

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-28' to each side of the equation.
28 + -28 + 8b = 68 + -28

Combine like terms: 28 + -28 = 0
0 + 8b = 68 + -28
8b = 68 + -28

Combine like terms: 68 + -28 = 40
8b = 40

Divide each side by '8'.
b = 5

Simplifying
b = 5

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