3(b+5)=r-2

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Solution for 3(b+5)=r-2 equation:


Simplifying
3(b + 5) = r + -2

Reorder the terms:
3(5 + b) = r + -2
(5 * 3 + b * 3) = r + -2
(15 + 3b) = r + -2

Reorder the terms:
15 + 3b = -2 + r

Solving
15 + 3b = -2 + r

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-15' to each side of the equation.
15 + -15 + 3b = -2 + -15 + r

Combine like terms: 15 + -15 = 0
0 + 3b = -2 + -15 + r
3b = -2 + -15 + r

Combine like terms: -2 + -15 = -17
3b = -17 + r

Divide each side by '3'.
b = -5.666666667 + 0.3333333333r

Simplifying
b = -5.666666667 + 0.3333333333r

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