3(b+5)=4-(2b-21)

Solution for 3(b+5)=4-(2b-21) equation:

3(b+5)=4-(2b-21)

We move all terms to the left:

3(b+5)-(4-(2b-21))=0

We multiply parentheses

3b-(4-(2b-21))+15=0


We calculate terms in parentheses: -(4-(2b-21)), so:

4-(2b-21)

determiningTheFunctionDomain
-(2b-21)+4

We get rid of parentheses

-2b+21+4

We add all the numbers together, and all the variables

-2b+25

Back to the equation:

-(-2b+25)


We get rid of parentheses

3b+2b-25+15=0

We add all the numbers together, and all the variables

5b-10=0

We move all terms containing b to the left, all other terms to the right

5b=10

b=10/5

b=2