3(b+5)=3(2b-5)

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Solution for 3(b+5)=3(2b-5) equation: 



3(b+5)=3(2b-5)

We move all terms to the left:

3(b+5)-(3(2b-5))=0

We multiply parentheses

3b-(3(2b-5))+15=0



We calculate terms in parentheses: -(3(2b-5)), so:

3(2b-5)

We multiply parentheses

6b-15

Back to the equation:

-(6b-15)



We get rid of parentheses

3b-6b+15+15=0

We add all the numbers together, and all the variables

-3b+30=0

We move all terms containing b to the left, all other terms to the right

-3b=-30

b=-30/-3

b=+10

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