3(b+4)-15=3(4-2b)

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Solution for 3(b+4)-15=3(4-2b) equation:



3(b+4)-15=3(4-2b)
We move all terms to the left:
3(b+4)-15-(3(4-2b))=0
We add all the numbers together, and all the variables
3(b+4)-(3(-2b+4))-15=0
We multiply parentheses
3b-(3(-2b+4))+12-15=0
We calculate terms in parentheses: -(3(-2b+4)), so:
3(-2b+4)
We multiply parentheses
-6b+12
Back to the equation:
-(-6b+12)
We add all the numbers together, and all the variables
3b-(-6b+12)-3=0
We get rid of parentheses
3b+6b-12-3=0
We add all the numbers together, and all the variables
9b-15=0
We move all terms containing b to the left, all other terms to the right
9b=15
b=15/9
b=1+2/3

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