3(b+4)+3=7b+3-2b

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Solution for 3(b+4)+3=7b+3-2b equation:


Simplifying
3(b + 4) + 3 = 7b + 3 + -2b

Reorder the terms:
3(4 + b) + 3 = 7b + 3 + -2b
(4 * 3 + b * 3) + 3 = 7b + 3 + -2b
(12 + 3b) + 3 = 7b + 3 + -2b

Reorder the terms:
12 + 3 + 3b = 7b + 3 + -2b

Combine like terms: 12 + 3 = 15
15 + 3b = 7b + 3 + -2b

Reorder the terms:
15 + 3b = 3 + 7b + -2b

Combine like terms: 7b + -2b = 5b
15 + 3b = 3 + 5b

Solving
15 + 3b = 3 + 5b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5b' to each side of the equation.
15 + 3b + -5b = 3 + 5b + -5b

Combine like terms: 3b + -5b = -2b
15 + -2b = 3 + 5b + -5b

Combine like terms: 5b + -5b = 0
15 + -2b = 3 + 0
15 + -2b = 3

Add '-15' to each side of the equation.
15 + -15 + -2b = 3 + -15

Combine like terms: 15 + -15 = 0
0 + -2b = 3 + -15
-2b = 3 + -15

Combine like terms: 3 + -15 = -12
-2b = -12

Divide each side by '-2'.
b = 6

Simplifying
b = 6

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