3(b+3)-4(2+b)=19

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Solution for 3(b+3)-4(2+b)=19 equation: 



3(b+3)-4(2+b)=19

We move all terms to the left:

3(b+3)-4(2+b)-(19)=0

We add all the numbers together, and all the variables

3(b+3)-4(b+2)-19=0

We multiply parentheses

3b-4b+9-8-19=0

We add all the numbers together, and all the variables

-1b-18=0

We move all terms containing b to the left, all other terms to the right

-b=18

b=18/-1

b=-18

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