3(b+3)+b=3(b-1)-2

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Solution for 3(b+3)+b=3(b-1)-2 equation:


Simplifying
3(b + 3) + b = 3(b + -1) + -2

Reorder the terms:
3(3 + b) + b = 3(b + -1) + -2
(3 * 3 + b * 3) + b = 3(b + -1) + -2
(9 + 3b) + b = 3(b + -1) + -2

Combine like terms: 3b + b = 4b
9 + 4b = 3(b + -1) + -2

Reorder the terms:
9 + 4b = 3(-1 + b) + -2
9 + 4b = (-1 * 3 + b * 3) + -2
9 + 4b = (-3 + 3b) + -2

Reorder the terms:
9 + 4b = -3 + -2 + 3b

Combine like terms: -3 + -2 = -5
9 + 4b = -5 + 3b

Solving
9 + 4b = -5 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
9 + 4b + -3b = -5 + 3b + -3b

Combine like terms: 4b + -3b = 1b
9 + 1b = -5 + 3b + -3b

Combine like terms: 3b + -3b = 0
9 + 1b = -5 + 0
9 + 1b = -5

Add '-9' to each side of the equation.
9 + -9 + 1b = -5 + -9

Combine like terms: 9 + -9 = 0
0 + 1b = -5 + -9
1b = -5 + -9

Combine like terms: -5 + -9 = -14
1b = -14

Divide each side by '1'.
b = -14

Simplifying
b = -14

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