3(b+22)=12b+30

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Solution for 3(b+22)=12b+30 equation: 



3(b+22)=12b+30

We move all terms to the left:

3(b+22)-(12b+30)=0

We multiply parentheses

3b-(12b+30)+66=0

We get rid of parentheses

3b-12b-30+66=0

We add all the numbers together, and all the variables

-9b+36=0

We move all terms containing b to the left, all other terms to the right

-9b=-36

b=-36/-9

b=+4

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