3(b+2)=6(b-2)=

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Solution for 3(b+2)=6(b-2)= equation:



3(b+2)=6(b-2)=
We move all terms to the left:
3(b+2)-(6(b-2))=0
We multiply parentheses
3b-(6(b-2))+6=0
We calculate terms in parentheses: -(6(b-2)), so:
6(b-2)
We multiply parentheses
6b-12
Back to the equation:
-(6b-12)
We get rid of parentheses
3b-6b+12+6=0
We add all the numbers together, and all the variables
-3b+18=0
We move all terms containing b to the left, all other terms to the right
-3b=-18
b=-18/-3
b=+6

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