3(b+2)=2(2b-1)

Solution for 3(b+2)=2(2b-1) equation:

Simplifying
3(b + 2) = 2(2b + -1)

Reorder the terms:
3(2 + b) = 2(2b + -1)
(2 * 3 + b * 3) = 2(2b + -1)
(6 + 3b) = 2(2b + -1)

Reorder the terms:
6 + 3b = 2(-1 + 2b)
6 + 3b = (-1 * 2 + 2b * 2)
6 + 3b = (-2 + 4b)

Solving
6 + 3b = -2 + 4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
6 + 3b + -4b = -2 + 4b + -4b

Combine like terms: 3b + -4b = -1b
6 + -1b = -2 + 4b + -4b

Combine like terms: 4b + -4b = 0
6 + -1b = -2 + 0
6 + -1b = -2

Add '-6' to each side of the equation.
6 + -6 + -1b = -2 + -6

Combine like terms: 6 + -6 = 0
0 + -1b = -2 + -6
-1b = -2 + -6

Combine like terms: -2 + -6 = -8
-1b = -8

Divide each side by '-1'.
b = 8

Simplifying
b = 8