3(b+2)+8=4b-4

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Solution for 3(b+2)+8=4b-4 equation: 



3(b+2)+8=4b-4

We move all terms to the left:

3(b+2)+8-(4b-4)=0

We multiply parentheses

3b-(4b-4)+6+8=0

We get rid of parentheses

3b-4b+4+6+8=0

We add all the numbers together, and all the variables

-1b+18=0

We move all terms containing b to the left, all other terms to the right

-b=-18

b=-18/-1

b=+18

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