3(b+2)+(b-3)=-5

Solution for 3(b+2)+(b-3)=-5 equation:

Simplifying
3(b + 2) + (b + -3) = -5

Reorder the terms:
3(2 + b) + (b + -3) = -5
(2 * 3 + b * 3) + (b + -3) = -5
(6 + 3b) + (b + -3) = -5

Reorder the terms:
6 + 3b + (-3 + b) = -5

Remove parenthesis around (-3 + b)
6 + 3b + -3 + b = -5

Reorder the terms:
6 + -3 + 3b + b = -5

Combine like terms: 6 + -3 = 3
3 + 3b + b = -5

Combine like terms: 3b + b = 4b
3 + 4b = -5

Solving
3 + 4b = -5

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 4b = -5 + -3

Combine like terms: 3 + -3 = 0
0 + 4b = -5 + -3
4b = -5 + -3

Combine like terms: -5 + -3 = -8
4b = -8

Divide each side by '4'.
b = -2

Simplifying
b = -2