3(b+12)=7(b-4)

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Solution for 3(b+12)=7(b-4) equation:


Simplifying
3(b + 12) = 7(b + -4)

Reorder the terms:
3(12 + b) = 7(b + -4)
(12 * 3 + b * 3) = 7(b + -4)
(36 + 3b) = 7(b + -4)

Reorder the terms:
36 + 3b = 7(-4 + b)
36 + 3b = (-4 * 7 + b * 7)
36 + 3b = (-28 + 7b)

Solving
36 + 3b = -28 + 7b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-7b' to each side of the equation.
36 + 3b + -7b = -28 + 7b + -7b

Combine like terms: 3b + -7b = -4b
36 + -4b = -28 + 7b + -7b

Combine like terms: 7b + -7b = 0
36 + -4b = -28 + 0
36 + -4b = -28

Add '-36' to each side of the equation.
36 + -36 + -4b = -28 + -36

Combine like terms: 36 + -36 = 0
0 + -4b = -28 + -36
-4b = -28 + -36

Combine like terms: -28 + -36 = -64
-4b = -64

Divide each side by '-4'.
b = 16

Simplifying
b = 16

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