3(b+1)=b-1

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Solution for 3(b+1)=b-1 equation: 



3(b+1)=b-1

We move all terms to the left:

3(b+1)-(b-1)=0

We multiply parentheses

3b-(b-1)+3=0

We get rid of parentheses

3b-b+1+3=0

We add all the numbers together, and all the variables

2b+4=0

We move all terms containing b to the left, all other terms to the right

2b=-4

b=-4/2

b=-2

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