3(b+1)=4b-q

Solution for 3(b+1)=4b-q equation:

Simplifying
3(b + 1) = 4b + -1q

Reorder the terms:
3(1 + b) = 4b + -1q
(1 * 3 + b * 3) = 4b + -1q
(3 + 3b) = 4b + -1q

Solving
3 + 3b = 4b + -1q

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
3 + 3b + -4b = 4b + -4b + -1q

Combine like terms: 3b + -4b = -1b
3 + -1b = 4b + -4b + -1q

Combine like terms: 4b + -4b = 0
3 + -1b = 0 + -1q
3 + -1b = -1q

Add '-3' to each side of the equation.
3 + -3 + -1b = -3 + -1q

Combine like terms: 3 + -3 = 0
0 + -1b = -3 + -1q
-1b = -3 + -1q

Divide each side by '-1'.
b = 3 + q

Simplifying
b = 3 + q