3(b+1)=4b-4

Solution for 3(b+1)=4b-4 equation:

Simplifying
3(b + 1) = 4b + -4

Reorder the terms:
3(1 + b) = 4b + -4
(1 * 3 + b * 3) = 4b + -4
(3 + 3b) = 4b + -4

Reorder the terms:
3 + 3b = -4 + 4b

Solving
3 + 3b = -4 + 4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
3 + 3b + -4b = -4 + 4b + -4b

Combine like terms: 3b + -4b = -1b
3 + -1b = -4 + 4b + -4b

Combine like terms: 4b + -4b = 0
3 + -1b = -4 + 0
3 + -1b = -4

Add '-3' to each side of the equation.
3 + -3 + -1b = -4 + -3

Combine like terms: 3 + -3 = 0
0 + -1b = -4 + -3
-1b = -4 + -3

Combine like terms: -4 + -3 = -7
-1b = -7

Divide each side by '-1'.
b = 7

Simplifying
b = 7