3(b+1)=4b+4

Solution for 3(b+1)=4b+4 equation:

Simplifying
3(b + 1) = 4b + 4

Reorder the terms:
3(1 + b) = 4b + 4
(1 * 3 + b * 3) = 4b + 4
(3 + 3b) = 4b + 4

Reorder the terms:
3 + 3b = 4 + 4b

Solving
3 + 3b = 4 + 4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
3 + 3b + -4b = 4 + 4b + -4b

Combine like terms: 3b + -4b = -1b
3 + -1b = 4 + 4b + -4b

Combine like terms: 4b + -4b = 0
3 + -1b = 4 + 0
3 + -1b = 4

Add '-3' to each side of the equation.
3 + -3 + -1b = 4 + -3

Combine like terms: 3 + -3 = 0
0 + -1b = 4 + -3
-1b = 4 + -3

Combine like terms: 4 + -3 = 1
-1b = 1

Divide each side by '-1'.
b = -1

Simplifying
b = -1