3(b+1)/2-4(b-2)/3=5

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Solution for 3(b+1)/2-4(b-2)/3=5 equation: 


b in (-oo:+oo)

(3*(b+1))/2-((4*(b-2))/3) = 5 // - 5

(3*(b+1))/2-((4*(b-2))/3)-5 = 0

(3*(b+1))/2+(-4/3)*(b-2)-5 = 0

(3*(b+1))/2-4/3*(b-2)-5 = 0

(3*(b+1))/2+(-4/3*2*(b-2))/2+(-5*2)/2 = 0

3*(b+1)-4/3*2*(b-2)-5*2 = 0

1/3*b-10+25/3 = 0

1/3*b-5/3 = 0

(1/3*b-5/3)/2 = 0

(1/3*b-5/3)/2 = 0 // * 2

1/3*b-5/3 = 0

1/3*b-5/3 = 0 // + 5/3

1/3*b = 5/3 // : 1/3

b = 5/3/1/3

b = 5

b = 5

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