3(ax+bx)=2(ax-b)

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Solution for 3(ax+bx)=2(ax-b) equation:


Simplifying
3(ax + bx) = 2(ax + -1b)
(ax * 3 + bx * 3) = 2(ax + -1b)
(3ax + 3bx) = 2(ax + -1b)
3ax + 3bx = (ax * 2 + -1b * 2)
3ax + 3bx = (2ax + -2b)

Solving
3ax + 3bx = 2ax + -2b

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-2ax' to each side of the equation.
3ax + -2ax + 3bx = 2ax + -2ax + -2b

Combine like terms: 3ax + -2ax = 1ax
1ax + 3bx = 2ax + -2ax + -2b

Combine like terms: 2ax + -2ax = 0
1ax + 3bx = 0 + -2b
1ax + 3bx = -2b

Add '-3bx' to each side of the equation.
1ax + 3bx + -3bx = -2b + -3bx

Combine like terms: 3bx + -3bx = 0
1ax + 0 = -2b + -3bx
1ax = -2b + -3bx

Divide each side by '1x'.
a = -2bx-1 + -3b

Simplifying
a = -2bx-1 + -3b

Reorder the terms:
a = -3b + -2bx-1

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