3(a-b)+2(a-b)-4(a-b)=

Solution for 3(a-b)+2(a-b)-4(a-b)= equation:

Simplifying
3(a + -1b) + 2(a + -1b) + -4(a + -1b) = 0
(a * 3 + -1b * 3) + 2(a + -1b) + -4(a + -1b) = 0
(3a + -3b) + 2(a + -1b) + -4(a + -1b) = 0
3a + -3b + (a * 2 + -1b * 2) + -4(a + -1b) = 0
3a + -3b + (2a + -2b) + -4(a + -1b) = 0
3a + -3b + 2a + -2b + (a * -4 + -1b * -4) = 0
3a + -3b + 2a + -2b + (-4a + 4b) = 0

Reorder the terms:
3a + 2a + -4a + -3b + -2b + 4b = 0

Combine like terms: 3a + 2a = 5a
5a + -4a + -3b + -2b + 4b = 0

Combine like terms: 5a + -4a = 1a
1a + -3b + -2b + 4b = 0

Combine like terms: -3b + -2b = -5b
1a + -5b + 4b = 0

Combine like terms: -5b + 4b = -1b
1a + -1b = 0

Solving
1a + -1b = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add 'b' to each side of the equation.
1a + -1b + b = 0 + b

Combine like terms: -1b + b = 0
1a + 0 = 0 + b
1a = 0 + b
Remove the zero:
1a = b

Divide each side by '1'.
a = b

Simplifying
a = b