3(a-5)-16a=12-2(a-3)

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Solution for 3(a-5)-16a=12-2(a-3) equation: 



3(a-5)-16a=12-2(a-3)

We move all terms to the left:

3(a-5)-16a-(12-2(a-3))=0

We add all the numbers together, and all the variables

-16a+3(a-5)-(12-2(a-3))=0

We multiply parentheses

-16a+3a-(12-2(a-3))-15=0



We calculate terms in parentheses: -(12-2(a-3)), so:

12-2(a-3)

determiningTheFunctionDomain
-2(a-3)+12

We multiply parentheses

-2a+6+12

We add all the numbers together, and all the variables

-2a+18

Back to the equation:

-(-2a+18)



We add all the numbers together, and all the variables

-13a-(-2a+18)-15=0

We get rid of parentheses

-13a+2a-18-15=0

We add all the numbers together, and all the variables

-11a-33=0

We move all terms containing a to the left, all other terms to the right

-11a=33

a=33/-11

a=-3

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