3(a-4)=1-0,05(2-a)

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Solution for 3(a-4)=1-0,05(2-a) equation: 



3(a-4)=1-0.05(2-a)

We move all terms to the left:

3(a-4)-(1-0.05(2-a))=0

We add all the numbers together, and all the variables

3(a-4)-(1-0.05(-1a+2))=0

We multiply parentheses

3a-(1-0.05(-1a+2))-12=0



We calculate terms in parentheses: -(1-0.05(-1a+2)), so:

1-0.05(-1a+2)

determiningTheFunctionDomain
-0.05(-1a+2)+1

We multiply parentheses

0.05a-0.1+1

We add all the numbers together, and all the variables

0.05a+0.9

Back to the equation:

-(0.05a+0.9)



We get rid of parentheses

3a-0.05a-0.9-12=0

We add all the numbers together, and all the variables

2.95a-12.9=0

We move all terms containing a to the left, all other terms to the right

2.95a=12.9

a=12.9/2.95

a=4+1/2.6818181818182

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