3(a-4)=-2(a+3)+14

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Solution for 3(a-4)=-2(a+3)+14 equation: 



3(a-4)=-2(a+3)+14

We move all terms to the left:

3(a-4)-(-2(a+3)+14)=0

We multiply parentheses

3a-(-2(a+3)+14)-12=0



We calculate terms in parentheses: -(-2(a+3)+14), so:

-2(a+3)+14

We multiply parentheses

-2a-6+14

We add all the numbers together, and all the variables

-2a+8

Back to the equation:

-(-2a+8)



We get rid of parentheses

3a+2a-8-12=0

We add all the numbers together, and all the variables

5a-20=0

We move all terms containing a to the left, all other terms to the right

5a=20

a=20/5

a=4

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