3(a-4)-12=5(a-1)

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Solution for 3(a-4)-12=5(a-1) equation: 



3(a-4)-12=5(a-1)

We move all terms to the left:

3(a-4)-12-(5(a-1))=0

We multiply parentheses

3a-(5(a-1))-12-12=0



We calculate terms in parentheses: -(5(a-1)), so:

5(a-1)

We multiply parentheses

5a-5

Back to the equation:

-(5a-5)



We add all the numbers together, and all the variables

3a-(5a-5)-24=0

We get rid of parentheses

3a-5a+5-24=0

We add all the numbers together, and all the variables

-2a-19=0

We move all terms containing a to the left, all other terms to the right

-2a=19

a=19/-2

a=-9+1/2

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