3(a-1)-a=3+2(a-3)

Solution for 3(a-1)-a=3+2(a-3) equation:

3(a-1)-a=3+2(a-3)

We move all terms to the left:

3(a-1)-a-(3+2(a-3))=0

We add all the numbers together, and all the variables

-1a+3(a-1)-(3+2(a-3))=0

We multiply parentheses

-1a+3a-(3+2(a-3))-3=0


We calculate terms in parentheses: -(3+2(a-3)), so:

3+2(a-3)

determiningTheFunctionDomain
2(a-3)+3

We multiply parentheses

2a-6+3

We add all the numbers together, and all the variables

2a-3

Back to the equation:

-(2a-3)


We add all the numbers together, and all the variables

2a-(2a-3)-3=0

We get rid of parentheses

2a-2a+3-3=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0