3(a+b-c)=

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Solution for 3(a+b-c)= equation:


Simplifying
3(a + b + -1c) = 0
(a * 3 + b * 3 + -1c * 3) = 0
(3a + 3b + -3c) = 0

Solving
3a + 3b + -3c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-3b' to each side of the equation.
3a + 3b + -3b + -3c = 0 + -3b

Combine like terms: 3b + -3b = 0
3a + 0 + -3c = 0 + -3b
3a + -3c = 0 + -3b
Remove the zero:
3a + -3c = -3b

Add '3c' to each side of the equation.
3a + -3c + 3c = -3b + 3c

Combine like terms: -3c + 3c = 0
3a + 0 = -3b + 3c
3a = -3b + 3c

Divide each side by '3'.
a = -1b + c

Simplifying
a = -1b + c

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