3(a+b)-2(b-a)+4(2a+3b)=

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Solution for 3(a+b)-2(b-a)+4(2a+3b)= equation:


Simplifying
3(a + b) + -2(b + -1a) + 4(2a + 3b) = 0
(a * 3 + b * 3) + -2(b + -1a) + 4(2a + 3b) = 0
(3a + 3b) + -2(b + -1a) + 4(2a + 3b) = 0

Reorder the terms:
3a + 3b + -2(-1a + b) + 4(2a + 3b) = 0
3a + 3b + (-1a * -2 + b * -2) + 4(2a + 3b) = 0
3a + 3b + (2a + -2b) + 4(2a + 3b) = 0
3a + 3b + 2a + -2b + (2a * 4 + 3b * 4) = 0
3a + 3b + 2a + -2b + (8a + 12b) = 0

Reorder the terms:
3a + 2a + 8a + 3b + -2b + 12b = 0

Combine like terms: 3a + 2a = 5a
5a + 8a + 3b + -2b + 12b = 0

Combine like terms: 5a + 8a = 13a
13a + 3b + -2b + 12b = 0

Combine like terms: 3b + -2b = 1b
13a + 1b + 12b = 0

Combine like terms: 1b + 12b = 13b
13a + 13b = 0

Solving
13a + 13b = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-13b' to each side of the equation.
13a + 13b + -13b = 0 + -13b

Combine like terms: 13b + -13b = 0
13a + 0 = 0 + -13b
13a = 0 + -13b
Remove the zero:
13a = -13b

Divide each side by '13'.
a = -1b

Simplifying
a = -1b

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