3(a+5)=-a(a-2)

Solution for 3(a+5)=-a(a-2) equation:

3(a+5)=-a(a-2)

We move all terms to the left:

3(a+5)-(-a(a-2))=0

We multiply parentheses

3a-(-a(a-2))+15=0


We calculate terms in parentheses: -(-a(a-2)), so:

-a(a-2)

We multiply parentheses

-a^2+2a

We add all the numbers together, and all the variables

-1a^2+2a

Back to the equation:

-(-1a^2+2a)


We get rid of parentheses

1a^2-2a+3a+15=0

We add all the numbers together, and all the variables

a^2+a+15=0

a = 1; b = 1; c = +15;
Δ = b2-4ac
Δ = 12-4·1·15
Δ = -59
Delta is less than zero, so there is no solution for the equation