3(a+4)=4a+12-a

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Solution for 3(a+4)=4a+12-a equation: 


Simplifying
3(a + 4) = 4a + 12 + -1a

Reorder the terms:
3(4 + a) = 4a + 12 + -1a
(4 * 3 + a * 3) = 4a + 12 + -1a
(12 + 3a) = 4a + 12 + -1a

Reorder the terms:
12 + 3a = 12 + 4a + -1a

Combine like terms: 4a + -1a = 3a
12 + 3a = 12 + 3a

Add '-12' to each side of the equation.
12 + -12 + 3a = 12 + -12 + 3a

Combine like terms: 12 + -12 = 0
0 + 3a = 12 + -12 + 3a
3a = 12 + -12 + 3a

Combine like terms: 12 + -12 = 0
3a = 0 + 3a
3a = 3a

Add '-3a' to each side of the equation.
3a + -3a = 3a + -3a

Combine like terms: 3a + -3a = 0
0 = 3a + -3a

Combine like terms: 3a + -3a = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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