3(a+4)=4(a+1)

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Solution for 3(a+4)=4(a+1) equation: 



3(a+4)=4(a+1)

We move all terms to the left:

3(a+4)-(4(a+1))=0

We multiply parentheses

3a-(4(a+1))+12=0



We calculate terms in parentheses: -(4(a+1)), so:

4(a+1)

We multiply parentheses

4a+4

Back to the equation:

-(4a+4)



We get rid of parentheses

3a-4a-4+12=0

We add all the numbers together, and all the variables

-1a+8=0

We move all terms containing a to the left, all other terms to the right

-a=-8

a=-8/-1

a=+8

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