3(a+4)-7(a+2)-4(3-a)=

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Solution for 3(a+4)-7(a+2)-4(3-a)= equation:


Simplifying
3(a + 4) + -7(a + 2) + -4(3 + -1a) = 0

Reorder the terms:
3(4 + a) + -7(a + 2) + -4(3 + -1a) = 0
(4 * 3 + a * 3) + -7(a + 2) + -4(3 + -1a) = 0
(12 + 3a) + -7(a + 2) + -4(3 + -1a) = 0

Reorder the terms:
12 + 3a + -7(2 + a) + -4(3 + -1a) = 0
12 + 3a + (2 * -7 + a * -7) + -4(3 + -1a) = 0
12 + 3a + (-14 + -7a) + -4(3 + -1a) = 0
12 + 3a + -14 + -7a + (3 * -4 + -1a * -4) = 0
12 + 3a + -14 + -7a + (-12 + 4a) = 0

Reorder the terms:
12 + -14 + -12 + 3a + -7a + 4a = 0

Combine like terms: 12 + -14 = -2
-2 + -12 + 3a + -7a + 4a = 0

Combine like terms: -2 + -12 = -14
-14 + 3a + -7a + 4a = 0

Combine like terms: 3a + -7a = -4a
-14 + -4a + 4a = 0

Combine like terms: -4a + 4a = 0
-14 + 0 = 0
-14 = 0

Solving
-14 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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