3(a+2)=2(a-4)

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Solution for 3(a+2)=2(a-4) equation: 



3(a+2)=2(a-4)

We move all terms to the left:

3(a+2)-(2(a-4))=0

We multiply parentheses

3a-(2(a-4))+6=0



We calculate terms in parentheses: -(2(a-4)), so:

2(a-4)

We multiply parentheses

2a-8

Back to the equation:

-(2a-8)



We get rid of parentheses

3a-2a+8+6=0

We add all the numbers together, and all the variables

a+14=0

We move all terms containing a to the left, all other terms to the right

a=-14

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