3(a+1)-5=9(6+2)+1

Solution for 3(a+1)-5=9(6+2)+1 equation:

Simplifying
3(a + 1) + -5 = 9(6 + 2) + 1

Reorder the terms:
3(1 + a) + -5 = 9(6 + 2) + 1
(1 * 3 + a * 3) + -5 = 9(6 + 2) + 1
(3 + 3a) + -5 = 9(6 + 2) + 1

Reorder the terms:
3 + -5 + 3a = 9(6 + 2) + 1

Combine like terms: 3 + -5 = -2
-2 + 3a = 9(6 + 2) + 1

Combine like terms: 6 + 2 = 8
-2 + 3a = 9(8) + 1

Multiply 9 * 8
-2 + 3a = 72 + 1

Combine like terms: 72 + 1 = 73
-2 + 3a = 73

Solving
-2 + 3a = 73

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 3a = 73 + 2

Combine like terms: -2 + 2 = 0
0 + 3a = 73 + 2
3a = 73 + 2

Combine like terms: 73 + 2 = 75
3a = 75

Divide each side by '3'.
a = 25

Simplifying
a = 25