3(a+)=6(a+2)-3

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Solution for 3(a+)=6(a+2)-3 equation: 



3(a+)=6(a+2)-3

We move all terms to the left:

3(a+)-(6(a+2)-3)=0

We add all the numbers together, and all the variables

3(+a)-(6(a+2)-3)=0

We multiply parentheses

3a-(6(a+2)-3)=0



We calculate terms in parentheses: -(6(a+2)-3), so:

6(a+2)-3

We multiply parentheses

6a+12-3

We add all the numbers together, and all the variables

6a+9

Back to the equation:

-(6a+9)



We get rid of parentheses

3a-6a-9=0

We add all the numbers together, and all the variables

-3a-9=0

We move all terms containing a to the left, all other terms to the right

-3a=9

a=9/-3

a=-3

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